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refraction · 21-04-2008, 09:44

correct, the formula to get a theoretical max is as follows

20480mbps / 8bits = 2560k/sec (2.5MB/sec)

this is the RAW transfer speed, not accounting for overheads due to the packet headers etc. I can usually hit 2300-2400k/sec or so, which sounds about right.

21-04-2008, 09:44	#8
refraction Inactive Join Date: Apr 2008 Location: Plymouth Services: XL Cable, XL TV, XL Phone, Mobile Posts: 44 $refraction is an unknown quantity at this point$	Re: Please clear this up download speed correct, the formula to get a theoretical max is as follows 20480mbps / 8bits = 2560k/sec (2.5MB/sec) this is the RAW transfer speed, not accounting for overheads due to the packet headers etc. I can usually hit 2300-2400k/sec or so, which sounds about right.
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