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Old 09-07-2004, 11:27   #25
altis
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Re: A Weighty ball problem?

Quote:
Originally Posted by zoombini
The written solution has arrived today. (The Engineer).

Number the balls 1 to 8.
Denote weighings W1, W2, W3.


W1 Put aside balls 7 & 8. Weigh balls 1, 2, 3 against 4, 5, 6.
If they balance, 7 or 8 is light/heavy.

W2 (a) Weigh 7 against any one of 1 to 6: this will show if 7 is heavy, light or the same.

W3 (a) If the same repeat with 8.

If 1, 2,3 is heavier than 4, 5, 6 on the first weighing then 1, 2 or 3 is heavy or 4, 5, or 6 is light.

W2 (b) Weigh 1, 2, 4 against 3, 7, 8.
If 1, 2, 4 are heavy then 1 or 2 is heavy.

W3 (b) Weigh 1 and any ball except 2. Either one will be the heavier, or, if the same, 2 is heavy.

If in W2 (b) 1,2,4 is light then either 4 is light or 3 is heavy.

W3 (c) Weigh 4 against anything but 3. If the same then 3 is heavy.

Hmm, too heavy for me, but I understand it now.
Hmm... indeed - surely that's only part of it.

Yes, it resolves whether 7 is heavy or light in stage 2a, whether 8 is heavy or light in stage 3a, whether 1 or 2 is heavy in stage 3b and whether 3 is heavy or 4 is light in stage 3c.

But what about the cases when 1 is light, 2 is light, 3 is light, 4 is heavy or anything to do with balls 5 or 6?
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