View Single Post
Old 07-07-2004, 13:04   #15
MetaWraith
Inactive
 
MetaWraith's Avatar
 
Join Date: Oct 2003
Location: 2nd CPU to the right & past the cache
Posts: 1,949
MetaWraith has a bronzed appealMetaWraith has a bronzed appeal
MetaWraith has a bronzed appealMetaWraith has a bronzed appealMetaWraith has a bronzed appealMetaWraith has a bronzed appealMetaWraith has a bronzed appealMetaWraith has a bronzed appealMetaWraith has a bronzed appeal
Send a message via ICQ to MetaWraith Send a message via AIM to MetaWraith Send a message via MSN to MetaWraith Send a message via Yahoo to MetaWraith
Re: A Weighty ball problem?

Now I've had time to take lunch, and write it up here's a solution
I think It's more or less what Danielf had, but with more detail.

STEP 1
Weigh 2 v 2
Possible results
A) pairs are unequal (heavier or lighter not known)
B) pairs are equal
Thus we have 4 balls known to be "good" and 4 balls still "suspect".

STEP 2)
Weigh 2 "suspect" balls v 2 "known good" balls
Possible results
C) pairs are unequal (heavier or lighter is now known)
D) pairs are equal (discard these)

STEP 3C
Weigh one of the "suspect" balls tested in STEP 2 against a "known good" ball
Possible Results
E) Balance equal (the other suspect is guilty)
F) Balance unequal (the chosen suspect is guilty)

STEP 3D
Weigh one of the "suspect" balls not tested in STEP 2 against a "known good" ball
G) Balance equal (the other suspect is guilty)
H) Balance unequal (the chosen suspect is guilty)

NOTE
In G) it is impossible to tell if the guilty ball is heaver or lighter without a further weighing
MetaWraith is offline   Reply With Quote