|
Re: A Weighty ball problem?
Quote:
|
Originally Posted by Matth
1: Weigh 2 against 2 - if this group are equal, they become your reference, the other group the sample, otherwise reverse it.
2: Weigh 2 of the sample against 2 of the reference - if equal, they move to the reference, otherwise the other two move to the reference.
3. Now out of the remaing two left in the sample, weigh ONE against one of the reference - if unequal, you've found it, otherwise it's the other one
|
Slightly different from my solution, but it works just the same. 
__________________
Remember kids: We are blessed with a listening, caring government.
|