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Old 07-07-2004, 12:27   #6
danielf
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Re: A Weighty ball problem?

Quote:
Originally Posted by zoombini
You only get 3 goes.
This is three goes. In the first go, you narrow it down to four (say ABCD). Then you check two of these to see if they are equal (say A and B). If they are, you only have two left, one of which includes the odd one out. If you now check if A and C are equal (and they are), the odd one out must be D. If A and C are not equal, it must be C.

If the first 4 are equal, you do step 2 and 3 with EFGH
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