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Solitaire?
Hello boys and girls,
I have a solitaire set, I am currently having a go at, I know the rules, how you have to jump over one ball with anouther to take it, and that there should be one ball left at the end in the centre, but is there some sort of technique that you have to employ? TIA |
Re: Solitaire?
I thought Solitaire was a card game you played when bored at work? :disturbd:
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Re: Solitaire?
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ahhh you mean this one
well then i aint got a clue:D |
Re: Solitaire?
lol, yup, thats the one.
I remember playing it about 10 years ago now, was fun, I remember anouther game with weird stones, that might have been made up though.... |
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IIRC you first have to try to end up with the only pieces left being in the following arrangement: X X XXX XXX XXX After that, there is a guaranteed solution. |
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hope this works from google images
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Re: Solitaire?
http://www.samizdat.com/hiq.html
I believe this provides a complete solution (and alternative solutions), if you can figure out the notation. :) |
Re: Solitaire?
heh, Im going to do what that guy did, and trace it back from the middle, looks like more fun :)
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Re: Solitaire?
I made one of them when I was at school.
Never played it much though, lost all the marbles etc. Still can't find my marbles..lol |
Re: Solitaire?
And when you've successfully finished Solitaire have a go at the Tower of Benares; it should occupy a rainy afternoon. It consists of 3 poles. On the first pole there are 64 disks with holes in their centres. Each disk has a different diameter and they are arranged so that the largest disk is at the bottom of the pole and the smallest at the top, so that it looks like a cone with the apex at the top.
The aim of the game is to transfer all of the disks to one of the other poles. The rules are quite simple. 1) Only one disk may be moved at a time and it must be placed on any one of the poles before another disk can be moved. 2) A smaller disk may be placed on a larger disk but a larger disk may not be placed on a smaller disk. |
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I like that one - it is actually quite easy once you have got the knack of it ;) |
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As a matter of interest, I once worked out that the minimum number of moves to solve it was (2^n) - 1 where n is the number of disks. |
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